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The equation of the line throgh the poin...

The equation of the line throgh the point `veca` parallel to the plane `vecr.vecn`=q and perpendicular to the line `vecr=vecb+tvecc` is (A) `vecr=veca+lamda (vecnxxvecc)` (B) `(vecr-veca)xx(vecnxxvecc)=0` (C) `vecr=vecb+lamda(vecnxxvecc)` (D) none of these

A

`vecr=veca+lamda(vecnxxvecc)`

B

`(vecr-veca)xx(vecnxxvecc)=0`

C

`vecr=vecb+lamda(vecnxxvecc)`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the equation of a line that satisfies two conditions: it passes through a given point \( \vec{a} \), is parallel to a specified plane, and is perpendicular to a given line. Let's break down the solution step by step. ### Step 1: Understand the conditions The line we are looking for must: 1. Pass through the point \( \vec{a} \). 2. Be parallel to the plane defined by the equation \( \vec{r} \cdot \vec{n} = q \). This means it must be perpendicular to the normal vector \( \vec{n} \) of the plane. 3. Be perpendicular to the line defined by \( \vec{r} = \vec{b} + t \vec{c} \). This means it must be perpendicular to the direction vector \( \vec{c} \) of this line. ### Step 2: Determine the direction vector of the required line Since the required line must be perpendicular to both \( \vec{n} \) and \( \vec{c} \), we can find its direction vector using the cross product: \[ \text{Direction vector} = \vec{n} \times \vec{c} \] ### Step 3: Write the equation of the line The general equation of a line in vector form that passes through a point \( \vec{a} \) and has a direction vector \( \vec{d} \) is given by: \[ \vec{r} = \vec{a} + \lambda \vec{d} \] Substituting our direction vector from Step 2, we have: \[ \vec{r} = \vec{a} + \lambda (\vec{n} \times \vec{c}) \] ### Step 4: Finalize the equation Thus, the equation of the required line is: \[ \vec{r} = \vec{a} + \lambda (\vec{n} \times \vec{c}) \] ### Step 5: Check the options Now, we compare this equation with the given options: - (A) \( \vec{r} = \vec{a} + \lambda (\vec{n} \times \vec{c}) \) - This matches our derived equation. - (B) \( (\vec{r} - \vec{a}) \times (\vec{n} \times \vec{c}) = 0 \) - This represents a different condition. - (C) \( \vec{r} = \vec{b} + \lambda (\vec{n} \times \vec{c}) \) - This does not match. - (D) None of these - Not applicable since we found a match. ### Conclusion The correct answer is: **(A) \( \vec{r} = \vec{a} + \lambda (\vec{n} \times \vec{c}) \)**

To solve the problem, we need to find the equation of a line that satisfies two conditions: it passes through a given point \( \vec{a} \), is parallel to a specified plane, and is perpendicular to a given line. Let's break down the solution step by step. ### Step 1: Understand the conditions The line we are looking for must: 1. Pass through the point \( \vec{a} \). 2. Be parallel to the plane defined by the equation \( \vec{r} \cdot \vec{n} = q \). This means it must be perpendicular to the normal vector \( \vec{n} \) of the plane. 3. Be perpendicular to the line defined by \( \vec{r} = \vec{b} + t \vec{c} \). This means it must be perpendicular to the direction vector \( \vec{c} \) of this line. ...
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CENGAGE ENGLISH-THREE-DIMENSIONAL GEOMETRY -MULTIPLE CORRECT ANSWER TYPE
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