The equation of the line `x+y+z-1=0`, `4x+y-2z+2=0` written in the symmetrical form is

Options

A. `(x+1)/(1)=(y-2)/(-2)= (z-0)/(1)`
B. `(x)/(1)= (y)/(-2)= (z-1)/(1)`
C. `(x+1//2)/(1)= (y-1)/(-2)= (z-1//2)/(1)`
D. `(x-1)/(2)= (y+2)/(-1)= (z-2)/(2)`

Answer

a,b,c

Explanation

`" "x+y+z-1=0`
`" "4x+y-2z+2=0`
Therefore, direction ratios of the line are `(-3, 6, -3)` i.e., `(1, -2, 1)`
Let `z= k`, then `x=k-1, y=2-2k`.
i.e., `(k-1, 2-2k, k)` is any point on the line
Therefore, `(-1, 2, 0), (0, 0, 1) and (-(1)/(2), 1, (1)/(2))` are points on the lines.