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For what values of p and q the system of...

For what values of p and q the system of equations `2x+py+6z=8, x+2y+qz=5, x+y+3z=4` has no solution. (a).`p=2, q ne 3`. (b).`p ne 2, q ne 3` (c). `p ne 2, q = 3` (d). `p =2, q=3`

A

`p=2, q ne 3`.

B

`p ne 2, q ne 3`

C

`p ne 2, q = 3`

D

`p =2, q=3`

Text Solution

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The correct Answer is:
To determine the values of \( p \) and \( q \) for which the system of equations has no solution, we will analyze the given equations: 1. \( 2x + py + 6z = 8 \) (Equation 1) 2. \( x + 2y + qz = 5 \) (Equation 2) 3. \( x + y + 3z = 4 \) (Equation 3) For a system of linear equations to have no solution, the determinant of the coefficients must be equal to zero. We will set up the determinant using the coefficients of \( x \), \( y \), and \( z \) from the equations. The coefficient matrix is: \[ \begin{bmatrix} 2 & p & 6 \\ 1 & 2 & q \\ 1 & 1 & 3 \end{bmatrix} \] The determinant of this matrix can be calculated using the formula for the determinant of a 3x3 matrix: \[ \text{Det} = a(ei - fh) - b(di - fg) + c(dh - eg) \] Where: - \( a = 2, b = p, c = 6 \) - \( d = 1, e = 2, f = q \) - \( g = 1, h = 1, i = 3 \) Calculating the determinant step by step: 1. **Calculate \( ei - fh \)**: \[ ei = 2 \cdot 3 = 6 \] \[ fh = q \cdot 1 = q \] \[ ei - fh = 6 - q \] 2. **Calculate \( di - fg \)**: \[ di = 1 \cdot 3 = 3 \] \[ fg = q \cdot 1 = q \] \[ di - fg = 3 - q \] 3. **Calculate \( dh - eg \)**: \[ dh = 1 \cdot 1 = 1 \] \[ eg = 2 \cdot 1 = 2 \] \[ dh - eg = 1 - 2 = -1 \] Now substituting these into the determinant formula: \[ \text{Det} = 2(6 - q) - p(3 - q) + 6(-1) \] Expanding this gives: \[ \text{Det} = 12 - 2q - 3p + pq - 6 \] \[ = pq - 3p - 2q + 6 \] Setting the determinant to zero for the system to have no solution: \[ pq - 3p - 2q + 6 = 0 \] Rearranging this, we can factor it: \[ pq - 3p - 2q + 6 = (q - 3)(2 - p) = 0 \] This gives us two equations: 1. \( q - 3 = 0 \) → \( q = 3 \) 2. \( 2 - p = 0 \) → \( p = 2 \) Thus, the values of \( p \) and \( q \) for which the system has no solution are \( p = 2 \) and \( q = 3 \). ### Final Answer: The correct option is (d) \( p = 2, q = 3 \).

To determine the values of \( p \) and \( q \) for which the system of equations has no solution, we will analyze the given equations: 1. \( 2x + py + 6z = 8 \) (Equation 1) 2. \( x + 2y + qz = 5 \) (Equation 2) 3. \( x + y + 3z = 4 \) (Equation 3) For a system of linear equations to have no solution, the determinant of the coefficients must be equal to zero. We will set up the determinant using the coefficients of \( x \), \( y \), and \( z \) from the equations. ...
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