Draw the graph of `f(x) = e^(sin x).`

Explanation

We have `y = f(x) = e^(sin x)`
`f(x + 2pi) = f(x)` for all `x in R`
Hence f(x) is periodic with period `2pi`.
So we need to draw the graph for the interval `[0, 2pi]` only.
Since the function is continuous, we selecet quadrant angles to plot point on the graph.
`f(0) = e^(sin 0) = e^(0) = 1`
`f(x) = 1, f(2pi) = 1`
`f(pi//2) = e^(sin(pi//2)) = e`
`f(3pi//2) = e^(sin(3pi//2)) = 1//e`
So we have the graph of the function as shown in the following figure. In intervals `[2pi, 4pi], [4pi, 6pi], ...` we repeat the graph which we get in the interval `[0, 2pi].`