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AB is a vertical pole resting at the end A on the level ground. P is a point on the level ground such that AP = 3AB and C Is the midpoint of AB. If AC and CB subtend angles `alpha` and `beta`, respectively, at P, then the value of tan`beta` is

A

`(18)/(19)`

B

`3/19`

C

`1/6`

D

`1/3`

Text Solution

Verified by Experts

On the basis of the given information , following diagram is obtained .

`tanbeta=tan((alpha+beta)-alpha)`
`=(1/3-1/6)/(1+(1)/(3).(1)/(6))=3/(19)`
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