The length of the shadow of a pole inclined at `10^@` to the vertical towards the sun is 2.05 metres, when theelevation of the sun is `38^@`. Then, find the length of the pole.

Options

A. `(2.05 sin 42^@)/(sin 38^@)`
B. `(2.05 sin 42^@)/(cos 42^@)`
C. `(2.05 sin 38^@)/(sin 42^@)`
D. `(2.05 sin 42^@)/(sin 38^@)`

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the Geometry
We have a pole inclined at an angle of \(10^\circ\) to the vertical. This means that the angle between the pole and the ground is \(90^\circ - 10^\circ = 80^\circ\). The elevation of the sun is \(38^\circ\), and the length of the shadow is \(2.05\) meters.

### Step 2: Draw a Diagram
Let's label the points:
- Let point A be the top of the pole.
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