The equation of a tangent to the parabola `y^2=""8x""i s""y""=""x""+""2` . The point on this line from which the other tangent to the parabola is perpendicular to the given tangent is (1) `(-1,""1)` (2) `(0,""2)` (3) `(2,""4)` (4) `(-2,""0)`

Explanation

From the graph of `(y-x)` against `(y+x)`, we have
`" "(y-x)/(y+x)= k (k gt 1)`
`rArr" "y-x=k(y+x)`
`rArr" "y(1-k)=x(1+k)`
`rArr" "y= ((1+k)/(1-k))x`
Now `" "(1+k)/(1-k)lt -1`
Hence the graph is the one which has slope less then -1, and the angle of the line is less than `135^(@)` with the positive `x`-axis.
Hence, the correct option is (c).