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Draw the graph of the function f(x)= x- ...

Draw the graph of the function `f(x)= x- |x-x^(2)|, -1 le x le 1` and find the points of non-differentiability.

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We have `y= f(x)=x- |x-x^(2)|`
`" "= {{:(x-(x^(2)-x)",",,x^(2)-x ge0),(x-(x-x^(2))",",,x^(2)-x lt 0):}`
`" "= {{:(x-(2x-x^(2))",",,xle0 or x ge 1),(x^(2)",",,0ltxlt1):}`
The graph of the function `y= 2x-x^(2)= x(2-x)` is a downward parabola intersecting the x-axis at `x=0 and x=2`.
Thus, the graph of the function `y= f(x)` is as follows:

Clearly from the graph the function is continuous but non-differentiable at `x=0, 1`.
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