Solve : `x^(2)- |x+2|+x gt 0`

Explanation

To solve the inequality \( x^2 - |x + 2| + x > 0 \), we will break it down into two cases based on the definition of the absolute value.

### Step 1: Identify the cases for the absolute value
The expression \( |x + 2| \) can be defined based on the value of \( x \):
- Case 1: \( x < -2 \) → \( |x + 2| = -(x + 2) = -x - 2 \)
- Case 2: \( x \geq -2 \) → \( |x + 2| = x + 2 \)

### Step 2: Solve Case 1 (when \( x < -2 \))
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