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Draw in graph of y=" cosec"^(-1)("cosec ...

Draw in graph of `y=" cosec"^(-1)("cosec x")`.

Text Solution

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`y = "cosec"^(-1) ("cosec x")`
`rArr" ""cosec "y=" cosec x"`
`rArr" "sin y = sin x`
Hence the graph of `y = "cosec"^(-1)("cosec" x)` is the same as that of `y = sin^(-1)(sin x)`, but excludng points `x=npi, n in Z`, where cosec x is not defined.
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