Solve the equation `sqrt(|sin^(-1)|"cos"||+|cos^1|sinx||)=sin^(-1)|cosx|-cos^(-1)|sinx|,(-pi)/2lt=xlt=pi/2dot`

Explanation

To solve the equation

\[ \sqrt{|\sin^{-1}(\cos x)| + |\cos^{-1}(\sin x)|} = \sin^{-1}(|\cos x|) - \cos^{-1}(|\sin x|), \quad -\frac{\pi}{2} < x < \frac{\pi}{2}, \]

we will follow these steps:

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