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Find the area bounded by y = sin^(-1) (s...

Find the area bounded by `y = sin^(-1) (sin x)` and x-axis for `x in [0, 100pi]`

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`y sin^(-1) (sin x)` is periodic with period `2 pi`
`:.` Required area `= 50 xx` (area bounded by `y = sin^(-1) (sin x)` and x a-axis for `x in [0, 2pi])`
Graph of `y = sin^(-1) (sin x) " for " x in [0, 2pi]` is as shown in the following figure.

Required area `= 50 xx (" area of " Delta ABC + "area of " Delta CDE)`
`= 100 xx ("area of " Delta ABC)`
`= 100 xx ((1)/(2) xx pi xx (pi)/(2))`
`25 pi^(2)`
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CENGAGE ENGLISH-INVERSE TRIGONOMETRIC FUNCTIONS-Illustration
  1. Solve sin^(-1) (sin 6x) = x, x in [0,pi]

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  2. Solve sin^(-1) [sin((2x^(2) + 4)/(1 + x^(2)))] lt pi -3

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  3. Find the area bounded by y = sin^(-1) (sin x) and x-axis for x in [0, ...

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  4. Find the value of x for which f(x) = 2 sin^(-1) sqrt(1 - x) + sin^(-1)...

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  5. Find the principal value of the following (i) cos^(-1) (cos 3) (ii) ...

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  6. Solve cos^(-1) (cos x) gt sin^(-1) (sin x), x in [0, 2pi]

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  7. Find the principal values of the following (i) tan^(-1) (tan. (2pi)/...

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  8. Find the number of solution of 2 tan^(-1) (tan x) = 6 - x

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  9. Write tan^(-1) x, x gt 0 in the form of other inverse trigonometric fu...

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  10. Find tan^(-1). (x)/(sqrt(a^(2) - x^(2))) in terms of sin^(-1), where x...

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  11. Prove that sin (cot^(-1) (tan (cos^(-1) x))) = x, x gt 0

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  12. If x<0, then prove that cos^(-1)x=pi-sin^(-1)sqrt(1-x^2)

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  13. Prove that cos^(-1) {sqrt((1 + x)/(2))} = (cos^(-1) x)/(2) , -1 lt x l...

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  14. Prove that tan^(-1) {(x)/(a + sqrt(a^(2) - x^(2)))} = (1)/(2) sin^(-1)...

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  15. Prove that sin^(-1) {(sqrt(1 + x) + sqrt(1 - x))/(2)} = (pi)/(4) + (co...

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  16. Prove that cos^(-1) ((1 - x^(2n))/(1 + x^(2n))) = 2 tan^(-1) x^(n), 0 ...

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  17. If x in [-1, 0], then find the value of cos^(-1) (2x^(2) - 1) - 2 sin^...

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  18. If (1)/(sqrt2) lt x lt 1, then prove that cos^(-1) x + cos^(-1) ((x + ...

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  19. Find the value of sin^(-1) (sin 5) + cos^(-1) (cos 10) + tan^(-1) {tan...

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  20. Find the minimum value of the function f(x) = (pi^(2))/(16 cot^(-1) (-...

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