In an NPN transistor `10^(10)` electrons enter the emitter in `10^(-6)`s and 2 % electrons recombine with holes in base then current gain `alpha` and `beta` are

In an n-p-n transistor 10^(10) electrons enter the emitter in 10^(-6) s, 3% of the electrons are lost in the base. The current transfer ratio is

In a npn transistor 10^(10) electrons enter the emitter in 10^(–6) s. 4% of the electrons are lost in the base. The current transfer ratio will be

In an n-p-n transistor 10^(10) electrons enter the emitter in 10^(-6) s. If 2% of the electrons are lost in the base, find the current transfer ratio and the current amplification factor.

In an n-p-n transistor 10^(10) electrons enter the emitter in 10^(-6) s. If 2% of the electrons are lost in the base, find the current transfer ratio and the current amplification factor.