Solve : `sin^(-1)x + sin^(-1) 2x = (pi)/(3)`

Explanation

To solve the equation \( \sin^{-1} x + \sin^{-1} 2x = \frac{\pi}{3} \), we will follow these steps:

### Step 1: Rewrite the equation
We start with the given equation:
\[ \sin^{-1} x + \sin^{-1} 2x = \frac{\pi}{3} \]
We can rearrange this to isolate one of the inverse sine terms:
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