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If the middle term in the expansion of `(x^2+1//x)^n` is `924` `x^6` , then find the value of `ndot`

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Since there is only one middle term here, n is even therefore `(n//2+1)` th term is the middle term. Hence,
`.^(n)C_(n//2)(x^(2))^(n//2) (1/x)^(n//2) = 924 x^(6)`
or `x^(n//2) = x^(6)`
or `n = 12` (also `.^(12)C_(6) = 924`)
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