Find (i) the last digit, (ii) the last two digits, and (iii) the last three digits of `17^(256)dot`

Explanation

To find the last digit, last two digits, and last three digits of \( 17^{256} \), we can use the Binomial Theorem. Here’s a step-by-step solution:

### Step 1: Rewrite the expression
We start by rewriting \( 17^{256} \) as:
\[ 17^{256} = (17^2)^{128} = 289^{128} \]

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