Home
Class 12
MATHS
Find the value of .^(20)C(0) xx .^(13)...

Find the value of
`.^(20)C_(0) xx .^(13)C_(10) - .^(20)C_(1) xx .^(12)C_(9) + .^(20)C_(2) xx .^(11)C_(8) - "……" + .^(20)C_(10)`.

Text Solution

AI Generated Solution

To solve the problem, we need to evaluate the expression: \[ ^{20}C_{0} \cdot ^{13}C_{10} - ^{20}C_{1} \cdot ^{12}C_{9} + ^{20}C_{2} \cdot ^{11}C_{8} - \ldots + (-1)^{10} \cdot ^{20}C_{10} \] This expression can be interpreted using the Binomial Theorem. The coefficients in the expression can be derived from the expansion of the binomials. ...
Promotional Banner

Topper's Solved these Questions

  • BINOMIAL THEOREM

    CENGAGE ENGLISH|Exercise Example|10 Videos
  • BINOMIAL THEOREM

    CENGAGE ENGLISH|Exercise Concept Application Exercise 8.1|17 Videos
  • AREA

    CENGAGE ENGLISH|Exercise Comprehension Type|2 Videos
  • CIRCLE

    CENGAGE ENGLISH|Exercise MATRIX MATCH TYPE|7 Videos

Similar Questions

Explore conceptually related problems

The value of ""^(40)C_(0) xx ""^(100)C_(40) _ ""^(40)C_(1) xx ""^(99)C_(40) + ""^(40)C_(2) xx ""^(98)C_(40) -"……." + ""^(40)C_(40) xx ""^(60)C_(40) is equal to "____" .

Find the value of (.^(10)C_(10))+(.^(10)C_(0)+.^(10)C_(1))+(.^(10)C_(0)+.^(10)C_(1)+.^(10)C_(2))+"...."+(.^(10)C_(0)+.^(10)C_(1)+.^(10)C_(2)+"....." + .^(10)C_(9)) .

If a= .^(20)C_(0) + .^(20)C_(3) + .^(20)C_(6) + .^(20)C_(9) + "…..", b = .^(20)C_(1) + .^(20)C_(4) + .^(20)C_(7) + "……"' and c = .^(20)C_(2) + .^(20)C_(5) + .^(20)C_(8) + "…..", then Value of a^(3) + b^(3) + c^(3) - 3abc is

The value of .^(20)C_(0)+.^(20)C_(1)+.^(20)C_(2)+.^(20)C_(3)+.^(20)C_(4)+.^(20)C_(12)+.^(20)C_(13)+.^(20)C_(14)+.^(20)C_(15) is

The sum of the series .^(20)C_(0)-.^(20)C_(1)+ .^(20)C_(2)-.^(20)C_(3)+...-.+ .^(20)C_(10) is -

The value of r for which .^(20)C_(r ), .^(20)C_(r - 1) .^(20)C_(1) + .^(20)C_(2) + …… + .^(20)C_(0) .^(20)C_(r ) is maximum, is

The value of r for which .^(20)C_(r ), .^(20)C_(r - 1) .^(20)C_(1) + .^(20)C_(2) + …… + .^(20)C_(0) .^(20)C_(r ) is maximum, is

Find the sum .^(n)C_(0) + 2 xx .^(n)C_(1) + xx .^(n)C_(2) + "….." + (n+1) xx .^(n)C_(n) .

Find the sum .^(n)C_(1) + 2 xx .^(n)C_(2) + 3 xx .^(n)C_(3) + "……" + n xx .^(n)C_(n) .

If a= ^(20)C_(0) + ^(20)C_(3) + ^(20)C_(6) + ^(20)C_(9) + "…..", b = ^(20)C_(1) + ^(20)C_(4) + ^(20)C_(7) + "… and c = ^(20)C_(2) + ^(20)C_(5) + ^(20)C_(8) + "…..", then Value of (a-b)^(2) + (b-c)^(2) + (c-a)^(2) is