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The probability that a married man watch...

The probability that a married man watches certain TV show is 0.4 and the probability that a married woman watches the show is 0.5. The probability that a man watches the show, given that his wife does, is 0.7. Then

A

the probability that married couple watches the show is `0.35`

B

the probability that a wife watches the show given that her husband does is `7//8`

C

the probability that at least one person of a married couple will watch the show is `0.55`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A, B, C

Let 'H' be the event that married man watches the show and 'W' be the probability that married women watches the show.
`thereforeP(H)=0.4P(W)=0.5,P(H//W)=0.7`
`a P(HnnW)=P(W)P(H//W)=0.5xx0.7=0.35`
`b P(W//H)=(P(HnnW))/(p(H))=(0.35)/(0.4)=7/8`
`cP(HuuW)=P(H)+P(W)-P(HnnW)`
`=0.4+0.5-0.35=0.35`
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