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Find the value of P such that the vertex...

Find the value of `P` such that the vertex of `y=x^2+2p x+13` is 4 units above the x-axis.

Text Solution

Verified by Experts

The given parabola is
`y=x^(2)+2px+13`
`ory=(x+p)^(2)+13-p^(2)`
`ory-(13-p^(2))=(x+p)^(2)`
So, the vertex is `(-p,13-p^(2))`.
Since the parabola is at a distance of 4 units above the x-axis,
`13-p^(2)=4`
`orp^(2)=9`
`orp=pm3`
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