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If (2,-8) is at an end of a focal chord ...

If `(2,-8)` is at an end of a focal chord of the parabola `y^2=32 x ,` then find the other end of the chord.

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We have parabola `y^(2)=32x`.
One end of focal chord is `P(2,-8)-=P(8t^(2),16t)`.
`:." "t=-1//2`
Thus, parameter of the other end Q of the focal chord PQ is 2.
Therefore, coordinates of Q are `(8(2)^(2),16(2))-=(32, 32)`.
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