A tangent to the parabola `y^2=8x` makes an angle of `45^0` with the straight line `y=3x+5.` Then find one of the points of contact.

Explanation

To solve the problem, we need to find the point of contact of a tangent to the parabola \( y^2 = 8x \) that makes an angle of \( 45^\circ \) with the line \( y = 3x + 5 \).

### Step-by-Step Solution:

1. **Identify the Parabola and its Parameters**:
The given parabola is \( y^2 = 8x \). We can rewrite it in the standard form \( y^2 = 4ax \), where \( 4a = 8 \). Thus, \( a = 2 \).

2. **Coordinates of a Point on the Parabola**:
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