Home
Class 12
MATHS
Let 3x-y-8=0 be the equation of tangen...

Let `3x-y-8=0` be the equation of tangent to a parabola at the point (7, 13). If the focus of the parabola is at (-1,-1). Its directrix is

Text Solution

AI Generated Solution

To find the equation of the directrix of the parabola given the tangent line and the focus, we can follow these steps: ### Step 1: Identify the given information We have the equation of the tangent line: \[ 3x - y - 8 = 0 \] The point of tangency is: \[ (7, 13) \] The focus of the parabola is: ...
Promotional Banner

Topper's Solved these Questions

  • PARABOLA

    CENGAGE ENGLISH|Exercise ILLUSTRATION 5.63|1 Videos
  • PARABOLA

    CENGAGE ENGLISH|Exercise ILLUSTRATION 5.64|1 Videos
  • PARABOLA

    CENGAGE ENGLISH|Exercise ILLUSTRATION 5.61|1 Videos
  • PAIR OF STRAIGHT LINES

    CENGAGE ENGLISH|Exercise Numberical Value Type|5 Videos
  • PERMUTATION AND COMBINATION

    CENGAGE ENGLISH|Exercise Comprehension|8 Videos

Similar Questions

Explore conceptually related problems

Let y=3x-8 be the equation of the tangent at the point (7, 13 ) lying on a parabola whose focus is at (-1,-1). Find the equation of directrix and the length of the latus rectum of the parabola.

Find the equation of the parabola having focus at(-1,-2) and directrix is x – 2y+3=0.

The focus of the parabola x^2-8x+2y+7=0 is

The equation of the parabola with the focus (0,-3), directrix y=3 is:

Find the equation of the parabola whose focus is at (-1, 1) and the directrix is x+y+1=0 .

Two tangents on a parabola are x-y=0 and x+y=0. S(2,3) is the focus of the parabola. The length of latus rectum of the parabola is

Find the equation of the parabola with vertex is at (2,1) and the directrix is x=y-1.

Find the equation of a parabola whose vertex at (-2,3) and the focus at (1,3) .

Find the equation of tangents drawn to the parabola y=x^2-3x+2 from the point (1,-1)dot

Find the equation of tangents drawn to the parabola y=x^2-3x+2 from the point (1,-1) .