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The vertex of a parabola is (2, 2) and t...

The vertex of a parabola is (2, 2) and the coordinats of its two extremities of latus rectum are `(-2,0)` and (6, 0). Then find the equation of the parabola.

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To find the equation of the parabola given the vertex and the coordinates of the extremities of the latus rectum, we can follow these steps: ### Step 1: Identify the vertex and the coordinates of the latus rectum The vertex of the parabola is given as \( (h, k) = (2, 2) \). The coordinates of the extremities of the latus rectum are given as \( (-2, 0) \) and \( (6, 0) \). ### Step 2: Find the focus of the parabola The focus of the parabola lies on the line segment joining the two extremities of the latus rectum. To find the focus, we first calculate the midpoint of the extremities: \[ \text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) = \left( \frac{-2 + 6}{2}, \frac{0 + 0}{2} \right) = \left( \frac{4}{2}, 0 \right) = (2, 0) \] ### Step 3: Determine the distance \( a \) The distance \( a \) is the distance from the vertex to the focus. Since the vertex is at \( (2, 2) \) and the focus is at \( (2, 0) \), we can calculate \( a \): \[ a = |k - y_{\text{focus}}| = |2 - 0| = 2 \] ### Step 4: Determine the orientation of the parabola Since the focus is below the vertex, the parabola opens downwards. ### Step 5: Write the equation of the parabola The standard form of the equation of a parabola that opens downwards is: \[ (x - h)^2 = -4a(y - k) \] Substituting \( h = 2 \), \( k = 2 \), and \( a = 2 \): \[ (x - 2)^2 = -4 \cdot 2 (y - 2) \] This simplifies to: \[ (x - 2)^2 = -8(y - 2) \] ### Final Equation Thus, the equation of the parabola is: \[ (x - 2)^2 = -8(y - 2) \]

To find the equation of the parabola given the vertex and the coordinates of the extremities of the latus rectum, we can follow these steps: ### Step 1: Identify the vertex and the coordinates of the latus rectum The vertex of the parabola is given as \( (h, k) = (2, 2) \). The coordinates of the extremities of the latus rectum are given as \( (-2, 0) \) and \( (6, 0) \). ### Step 2: Find the focus of the parabola The focus of the parabola lies on the line segment joining the two extremities of the latus rectum. To find the focus, we first calculate the midpoint of the extremities: ...
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CENGAGE ENGLISH-PARABOLA-Concept Applications Exercise 5.2
  1. If the focus and vertex of a parabola are the points (0, 2) and (0, 4)...

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  2. Find the equation of parabola whose focus is (0,1) and the directrix i...

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  3. Find the vertex, focus and directrix of the parabola x^(2)=2(2x+y).

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  4. The vertex of a parabola is (2, 2) and the coordinats of its two ex...

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  5. A parabola passes through the point the point (1,2), (2,1), (3,4) and ...

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  6. Find the length of the common chord of the parabola y^2=4(x+3) and the...

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  7. The equation of the latus rectum of a parabola is x+y=8 and the equati...

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  8. Find the length of the latus rectum of the parabola whose focus is at ...

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  9. If (a ,b) is the midpoint of a chord passing through the vertex of the...

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  10. about to only mathematics

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  11. Plot the region in the first quadrant in which points are nearer to th...

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  12. Prove that the locus of a point, which moves so that its distance from...

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  13. Prove that the locus of the center of a circle, which intercepts a cho...

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  14. Find the equation of the parabola whose focus is S(-1,1) and directrix...

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  15. The axis of parabola is along the line y=x and the distance of its ver...

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  16. Find the equation of parabola whose focus is (0,1) and the directrix i...

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  17. Find the vertex, focus and directrix of the parabola x^(2)=2(2x+y).

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