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A circle is drawn to pass through the ex...

A circle is drawn to pass through the extremities of the latus rectum of the parabola `y^2=8xdot` It is given that this circle also touches the directrix of the parabola. Find the radius of this circle.

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To solve the problem step by step, we will find the radius of the circle that passes through the extremities of the latus rectum of the parabola \( y^2 = 8x \) and also touches the directrix of the parabola. ### Step 1: Identify the parameters of the parabola The given parabola is \( y^2 = 8x \). We can rewrite it in the standard form \( y^2 = 4ax \), where \( 4a = 8 \). **Calculation:** \[ 4a = 8 \implies a = 2 \] ### Step 2: Find the focus and directrix of the parabola For the parabola \( y^2 = 4ax \): - The focus is at \( (a, 0) = (2, 0) \). - The directrix is the line \( x = -a = -2 \). ### Step 3: Find the extremities of the latus rectum The latus rectum of a parabola is a line segment perpendicular to the axis of symmetry that passes through the focus. The length of the latus rectum is \( 4a \). **Calculation:** \[ \text{Length of latus rectum} = 4a = 8 \] The extremities of the latus rectum can be found at: \[ \left( a, \pm 2a \right) = \left( 2, \pm 4 \right) \] Thus, the points are \( (2, 4) \) and \( (2, -4) \). ### Step 4: Determine the diameter of the circle The diameter of the circle that passes through the points \( (2, 4) \) and \( (2, -4) \) is the distance between these two points. **Calculation:** \[ \text{Diameter} = \text{Distance between } (2, 4) \text{ and } (2, -4) = 4 - (-4) = 8 \] ### Step 5: Find the radius of the circle The radius \( r \) of the circle is half of the diameter. **Calculation:** \[ r = \frac{\text{Diameter}}{2} = \frac{8}{2} = 4 \] ### Step 6: Verify that the circle touches the directrix Since the circle is drawn considering the latus rectum as the diameter, it will touch the directrix \( x = -2 \). The center of the circle is at \( (2, 0) \) and the radius is \( 4 \). The distance from the center to the directrix is: \[ \text{Distance} = 2 - (-2) = 4 \] This confirms that the circle touches the directrix. ### Final Answer The radius of the circle is \( \boxed{4} \). ---

To solve the problem step by step, we will find the radius of the circle that passes through the extremities of the latus rectum of the parabola \( y^2 = 8x \) and also touches the directrix of the parabola. ### Step 1: Identify the parameters of the parabola The given parabola is \( y^2 = 8x \). We can rewrite it in the standard form \( y^2 = 4ax \), where \( 4a = 8 \). **Calculation:** \[ 4a = 8 \implies a = 2 ...
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