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Let L be a normal to the parabola y^2=4x...

Let `L` be a normal to the parabola `y^2=4x dot` If `L` passes through the point (9, 6), then `L` is given by (a) `y-x+3=0` (b) `y+3x-33=0` (c) `y+x-15=0` (d) `y-2x+12=0`

A

y-x+3=0

B

y+3x-33=0

C

y+x-15=0

D

y-2x+12=0

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
1,3,4
`y^(2)=4x`
The eqution of normal is `y=mx-2m-m^(3)`.
It passes through (9,6). So,
`m^(3)-7m+6=0`
`or(m-1)(m-2)(m-3)=0`
`orm=1,2,-3`
`:." normal are "y-x+3=0,y+3x-33=0,0y-2x+12=0`
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