Let the vectors `veca and vecb` be such that `|veca|=3and|vecb|=sqrt2/3"then|" vecaxxvecb`is a unit vector. If the angle between `veca and vecb` is ?

Explanation

To solve the problem, we need to find the angle between the vectors \(\vec{a}\) and \(\vec{b}\) given that the magnitudes of the vectors are \(|\vec{a}| = 3\) and \(|\vec{b}| = \frac{\sqrt{2}}{3}\), and that the magnitude of the cross product \(|\vec{a} \times \vec{b}|\) is a unit vector (which means its magnitude is 1).

### Step-by-Step Solution:

1. **Understanding the Cross Product Magnitude**:
The magnitude of the cross product of two vectors \(\vec{a}\) and \(\vec{b}\) is given by the formula:
\[
|\vec{a} \times \vec{b}| = |\vec{a}| |\vec{b}| \sin \theta
...