Find th altitude of a parallelepiped whose three coterminous edges are vectors `vecA=hati+hatj+hatk,vecB=2hati+4hatj-hatkand vecC=hati+hatj+3hatk "with" vecA and vecB` as the sides of the base of the parallelepiped .

Explanation

To find the altitude of the parallelepiped whose three coterminous edges are given by the vectors \(\vec{A} = \hat{i} + \hat{j} + \hat{k}\), \(\vec{B} = 2\hat{i} + 4\hat{j} - \hat{k}\), and \(\vec{C} = \hat{i} + \hat{j} + 3\hat{k}\), with \(\vec{A}\) and \(\vec{B}\) as the sides of the base, we can follow these steps:

### Step 1: Calculate the Cross Product \(\vec{A} \times \vec{B}\)
To find the area of the base, we first need to compute the cross product of vectors \(\vec{A}\) and \(\vec{B}\).

\[
\vec{A} \times \vec{B} =
\begin{vmatrix}
...