Let `veca,vecb and vecc` be the non zero vectors such that `(vecaxxvecb)xxvecc=1/3 |vecb||vecc|veca.` if theta is the acute angle between the vectors `vecb and veca` then theta equals (A) `1/3` (B) `sqrt(2)/3` (C) `2/3` (D) `2sqrt(2)/3`

Explanation

To solve the problem, we need to analyze the given equation involving the vectors \(\vec{a}\), \(\vec{b}\), and \(\vec{c}\):

\[ (\vec{a} \times \vec{b}) \times \vec{c} = \frac{1}{3} |\vec{b}| |\vec{c}| \vec{a} \]

### Step 1: Use the vector triple product identity
We can use the vector triple product identity, which states that:
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