A vector `(vecd)` is equally inclined to three vectors `veca= hati - hatj + hatk, vecb = 2 hati + hatj and vecc = 3hatj - 2hatk` let `vecx ,vecy, vecz` be three in the plane of `veca, vecb , vecb, vecc, vecc, veca` respectively, then

Options

A. `vecx.vecd=-1`
B. `vecy.vecd= 1`
C. vecz.vecd=0`
D. vecr.vecd=0, " where " vecr=lambda vecx + mu vecy +deltavecz`

Answer

c.d

Explanation

Since `[veca vecb vecc] =0, veca, vecb and vecc` are coplanar vectors.
Further, since, `vecd` is equally inclined to `veca ,vecb and vecc,`
`vecd.veca =vecd.vecb = vecd.vecc=0`
`vecd.vecx =vecd.vecy = vecd.vecz =0`
`vecd.vecr =0`