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Vertices of a parallelogram taken in order are A, ( 2,-1,4) , B (1,0,-1) , C ( 1,2,3) and D (x,y,z) The distance between the parallel lines AB and CD is

A

14, 4,2

B

2,4,14

C

4,2,14

D

2,14,4

Text Solution

Verified by Experts

The correct Answer is:
d
vector normal to the plane
`vec(AD)xxvec(AB)+(7hati+2hatj-hatk)`
Projection on xy=2
Projection on yx= 14
projection on zx = 4
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CENGAGE ENGLISH-DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS -Comprehension type
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