In a binomial distribution B `(b, p=(1)/(4)),` if the probability of at least one success is greater than or equal to `9/10,` then n is greater than

Options

A. `(1)/(log_(10)4-log_(10)3)`
B. `(1)/(log_(10)4+log_(10)3)`
C. `(9)/(log_(10)4-log_(10)3)`
D. `(4)/(log_(10)4-log_(10)3)`

Answer

A

Explanation

According to the question
`1-q^(n)ge9/10`
`implies((3)/(4))^(n)ge1/10`
`impliesnge-log_(3/4)10`
`=nge(1)/(log_(10)4-log_(10)3)`