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If f(x-y), f(x) f(y), and f(x+y) are in ...

If `f(x-y), f(x) f(y), and f(x+y)` are in A.P. for all x, y, and `f(0) ne 0,` then

A

`f(4)=f(-4)`

B

`f(2)+f(-2)=0`

C

`f'(4)+f'(-4)=0`

D

`f'(2)=f'(-2)`

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To solve the problem, we need to show that if \( f(x-y), f(x)f(y), \) and \( f(x+y) \) are in arithmetic progression (A.P.) for all \( x \) and \( y \), and \( f(0) \neq 0 \), then we can derive certain properties of the function \( f \). ### Step-by-Step Solution: 1. **Understanding A.P. Condition**: Since \( f(x-y), f(x)f(y), f(x+y) \) are in A.P., we can write the condition for A.P.: \[ 2f(x)f(y) = f(x-y) + f(x+y) ...
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