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Consider the parabola whose focus is at ...

Consider the parabola whose focus is at (0,0) and tangent at vertex is x-y+1=0
Tangents drawn to the parabola at the extremities of the chord 3x+2y=0 intersect at what angle ?

A

`pi//6`

B

`pi//3`

C

`pi//2`

D

none of these

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To solve the problem, we need to find the angle at which the tangents drawn to the parabola at the extremities of the chord \(3x + 2y = 0\) intersect. The parabola has its focus at the origin (0,0) and a tangent at the vertex given by the equation \(x - y + 1 = 0\). ### Step-by-Step Solution: 1. **Identify the Parabola**: The focus of the parabola is at (0,0) and the tangent at the vertex is given by \(x - y + 1 = 0\). This line can be rewritten as \(y = x + 1\). 2. **Find the Directrix**: The distance from the focus to the tangent line can be calculated using the formula for the distance from a point to a line: \[ \text{Distance} = \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}} \] Here, \(A = 1\), \(B = -1\), \(C = 1\), and the point is (0,0): \[ \text{Distance} = \frac{|1 \cdot 0 - 1 \cdot 0 + 1|}{\sqrt{1^2 + (-1)^2}} = \frac{1}{\sqrt{2}} \] The directrix is parallel to the tangent and located at a distance of \(2 \times \frac{1}{\sqrt{2}} = \sqrt{2}\) from the focus. Thus, the equation of the directrix is: \[ x - y + k = 0 \quad \text{where } k = -2 \] Therefore, the directrix is \(x - y - 2 = 0\). 3. **Equation of the Parabola**: The equation of the parabola can be derived from the definition of a parabola: the distance from any point on the parabola to the focus is equal to the distance to the directrix. The general form of the parabola is: \[ y^2 = 4px \] Here, \(p\) is the distance from the focus to the directrix. Since the directrix is at \(y = x - 2\), we can derive the equation of the parabola. 4. **Find the Points of Intersection with the Chord**: The chord given is \(3x + 2y = 0\) or \(y = -\frac{3}{2}x\). We can substitute this into the parabola's equation to find the points of intersection. 5. **Find the Tangents at Extremities**: The tangents at the points of intersection can be found using the point-slope form of the tangent line equation. 6. **Calculate the Angle Between the Tangents**: The angle \(\theta\) between two lines with slopes \(m_1\) and \(m_2\) is given by: \[ \tan(\theta) = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right| \] If the tangents are perpendicular, then \(m_1 m_2 = -1\), which implies that the angle between them is \(90^\circ\) or \(\frac{\pi}{2}\). ### Conclusion: The tangents drawn to the parabola at the extremities of the chord \(3x + 2y = 0\) intersect at an angle of \(90^\circ\) (or \(\frac{\pi}{2}\)).

To solve the problem, we need to find the angle at which the tangents drawn to the parabola at the extremities of the chord \(3x + 2y = 0\) intersect. The parabola has its focus at the origin (0,0) and a tangent at the vertex given by the equation \(x - y + 1 = 0\). ### Step-by-Step Solution: 1. **Identify the Parabola**: The focus of the parabola is at (0,0) and the tangent at the vertex is given by \(x - y + 1 = 0\). This line can be rewritten as \(y = x + 1\). 2. **Find the Directrix**: ...
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