Home
Class 12
MATHS
The postion vectors of the vertices of a...

The postion vectors of the vertices of a quadrilateral with A as origin are `B(vecb),D(vecd) and C (l vecb+m vecd)` . Prove that the area of the quadrilateral is `1/2(l+m)|vecb xx vecd|`.

Text Solution

Verified by Experts

Area of quandrilateral is `1/2|vec(AC)xxvec(BD)|=1/2|(lvecb+mvecd)xx(vecd-vecb)|`
`= 1/2 |lvecbxxvecd - mvecd xxvecb|`
`=1/2 ( l+m)|vecbxxvecd|`
Promotional Banner

Topper's Solved these Questions

  • DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS

    CENGAGE ENGLISH|Exercise Exercise 2.1|18 Videos
  • DIFFERENT PRODUCTS OF VECTORS AND THEIR GEOMETRICAL APPLICATIONS

    CENGAGE ENGLISH|Exercise Exercise 2.2|15 Videos
  • DETERMINANTS

    CENGAGE ENGLISH|Exercise All Questions|264 Videos
  • DIFFERENTIAL EQUATIONS

    CENGAGE ENGLISH|Exercise Matrix Match Type|5 Videos

Similar Questions

Explore conceptually related problems

The postion vectors of the vertrices fo aquadrilateral with A as origian are B(vecb),D(vecd) and C (l vecb+m vecd) . Prove that the area of the quadrilateral is 1/2(l+m)|vecb xx vecd| .

The position vectors of the vertices of a quadrilateral with A as origin are B( vec b),D( vec d)a n dC(l vec b+m vec d)dot Prove that the area of the quadrialateral is 1/2(l+m)| vec bxx vec d|dot

The position vectors of the vertices A, B and C of a triangle are three unit vectors veca, vecb and vecc respectively. A vector vecd is such that vecd.hata =vecd. Hatb=vecd.hatc and vecd= lambda (hatb + hatc) . Then triangle ABC is

The position vectors of the vertices A, B and C of a triangle are three unit vectors veca, vecb and vecc respectively. A vector vecd is such that vecd.hata =vecd. hatb=vecd.hatc and vecd= lambda (hatb + hatc) . Then triangle ABC is

If veca,vecb,vecc and vecd are the position vectors of the vertices of a cycle quadrilateral ABCD, prove that (|vecaxxvecb+vecb xxvecd+vecd xxveca|)/((vecb-veca).(vecd-veca))+(|vecbxxvecc+veccxxvecd+vecd+vecd xx vecb|)/((vecb-vecc).(vecd-vecc))

If veca,vecb,vec c,vecd are the position vectors of the verticles of a cyclic quadrilateral ABCd prove that (|vecaxxvecb+vecbxxvecd+vecd xxveca|)/((vecb-veca).(vecd-veca))+(|vecbxxvec c+veccxxvecd+vecd xxvecb|)/((vecb-vecc).(vecd-vecc))=0

Given vecC = vecA xx vecB and vecD = vecB xx vecA . What is the angle between vecC and vecD ?

If vecA xx vecB = vecC+ vecD , them select the correct alternative:

Prove that the perpendiculasr distanceof as point with position vector veca from the plane thorugh three points with position vectors vecb,vecc, vecd is ([veca vecc vecd]+[veca vecd vecb]+[veca vecb vecc]-[vecb vecc vecd])/(|vecbxxvecc+veccxxvecd+vecdxvecb|)

Let the pair of vector veca,vecb and vecc,vecd each determine a plane. Then the planes are parallel if