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The vectors which is/are coplanar with v...

The vectors which is/are coplanar with vectors `hati+hatj+2hatk and hati+2hatj+hatk` and perpendicular to the vector `hati+hatj+hatk ` is /are (A) `hatj-hatk` (B) `-hati+hatj` (C) `hati-hatj` (D) `-hatj+hatk`

A

`hatj - hatk`

B

`-hati + hatj`

C

`hati -hatj`

D

`-hatj +hatk`

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To solve the problem, we need to find the vectors that are coplanar with the vectors \( \hat{i} + \hat{j} + 2\hat{k} \) and \( \hat{i} + 2\hat{j} + \hat{k} \), and also perpendicular to the vector \( \hat{i} + \hat{j} + \hat{k} \). ### Step-by-Step Solution: 1. **Define the given vectors**: Let: \[ \mathbf{A} = \hat{i} + \hat{j} + 2\hat{k} \] \[ \mathbf{B} = \hat{i} + 2\hat{j} + \hat{k} \] \[ \mathbf{C} = \hat{i} + \hat{j} + \hat{k} \] 2. **Find a general vector coplanar with \(\mathbf{A}\) and \(\mathbf{B}\)**: Any vector \(\mathbf{R}\) that is coplanar with \(\mathbf{A}\) and \(\mathbf{B}\) can be expressed as: \[ \mathbf{R} = \lambda \mathbf{A} + \mu \mathbf{B} \] where \(\lambda\) and \(\mu\) are scalars. 3. **Substitute \(\mathbf{A}\) and \(\mathbf{B}\)**: \[ \mathbf{R} = \lambda (\hat{i} + \hat{j} + 2\hat{k}) + \mu (\hat{i} + 2\hat{j} + \hat{k}) \] Expanding this gives: \[ \mathbf{R} = (\lambda + \mu)\hat{i} + (\lambda + 2\mu)\hat{j} + (2\lambda + \mu)\hat{k} \] 4. **Condition for perpendicularity**: The vector \(\mathbf{R}\) must also be perpendicular to \(\mathbf{C}\). For two vectors to be perpendicular, their dot product must equal zero: \[ \mathbf{R} \cdot \mathbf{C} = 0 \] Therefore: \[ (\lambda + \mu) + (\lambda + 2\mu) + (2\lambda + \mu) = 0 \] Simplifying this: \[ 4\lambda + 4\mu = 0 \] or \[ \lambda + \mu = 0 \quad \Rightarrow \quad \mu = -\lambda \] 5. **Substituting \(\mu\) back into \(\mathbf{R}\)**: Substitute \(\mu = -\lambda\) into \(\mathbf{R}\): \[ \mathbf{R} = \lambda (\hat{i} + \hat{j} + 2\hat{k}) - \lambda (\hat{i} + 2\hat{j} + \hat{k}) \] This simplifies to: \[ \mathbf{R} = \lambda \left( \hat{j} - \hat{k} \right) \] 6. **Identifying the vectors**: The vector \(\mathbf{R}\) can be expressed as: \[ \mathbf{R} = \lambda (\hat{j} - \hat{k}) \] This means that \(\hat{j} - \hat{k}\) is one of the vectors that satisfy the conditions. 7. **Check the options**: - (A) \( \hat{j} - \hat{k} \) is valid. - (B) \( -\hat{i} + \hat{j} \) does not match. - (C) \( \hat{i} - \hat{j} \) does not match. - (D) \( -\hat{j} + \hat{k} \) can be obtained by taking \(\lambda = -1\). ### Final Answer: The vectors that are coplanar with \( \hat{i} + \hat{j} + 2\hat{k} \) and \( \hat{i} + 2\hat{j} + \hat{k} \), and perpendicular to \( \hat{i} + \hat{j} + \hat{k} \) are: - (A) \( \hat{j} - \hat{k} \) - (D) \( -\hat{j} + \hat{k} \)

To solve the problem, we need to find the vectors that are coplanar with the vectors \( \hat{i} + \hat{j} + 2\hat{k} \) and \( \hat{i} + 2\hat{j} + \hat{k} \), and also perpendicular to the vector \( \hat{i} + \hat{j} + \hat{k} \). ### Step-by-Step Solution: 1. **Define the given vectors**: Let: \[ \mathbf{A} = \hat{i} + \hat{j} + 2\hat{k} ...
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