If `sin(120^0-alpha)=sin(120^0-beta),0 lt alpha,beta lt pi, then find the relation between (alpha and betadot)`

Explanation

To solve the problem, we start with the equation given in the question:

\[ \sin(120^\circ - \alpha) = \sin(120^\circ - \beta) \]

### Step 1: Use the property of the sine function
From the property of sine, we know that if \( \sin A = \sin B \), then:

\[ A = B + 360^\circ n \quad \text{or} \quad A = 180^\circ - B + 360^\circ n \]
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