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Find the value of tan. pi/20tan. (3pi)/2...

Find the value of `tan. pi/20tan. (3pi)/20tan. (5pi)/20tan. (7pi)/20tan. (9pi)/20`.

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To find the value of \( \tan \frac{\pi}{20} \tan \frac{3\pi}{20} \tan \frac{5\pi}{20} \tan \frac{7\pi}{20} \tan \frac{9\pi}{20} \), we can follow these steps: ### Step 1: Write the expression We start with the expression: \[ \tan \frac{\pi}{20} \tan \frac{3\pi}{20} \tan \frac{5\pi}{20} \tan \frac{7\pi}{20} \tan \frac{9\pi}{20} \] ### Step 2: Use the identity for complementary angles We know that: \[ \tan\left(\frac{\pi}{2} - \theta\right) = \cot \theta \] We can express \( \tan \frac{7\pi}{20} \) and \( \tan \frac{9\pi}{20} \) as: \[ \tan \frac{7\pi}{20} = \tan\left(\frac{\pi}{2} - \frac{3\pi}{20}\right) = \cot \frac{3\pi}{20} \] \[ \tan \frac{9\pi}{20} = \tan\left(\frac{\pi}{2} - \frac{\pi}{20}\right) = \cot \frac{\pi}{20} \] ### Step 3: Substitute the complementary angles Now, substituting these values into the expression, we get: \[ \tan \frac{\pi}{20} \tan \frac{3\pi}{20} \tan \frac{5\pi}{20} \cot \frac{3\pi}{20} \cot \frac{\pi}{20} \] ### Step 4: Simplify using cotangent identities Using the identity \( \cot \theta = \frac{1}{\tan \theta} \), we can rewrite the expression: \[ \tan \frac{\pi}{20} \tan \frac{3\pi}{20} \tan \frac{5\pi}{20} \cdot \frac{1}{\tan \frac{3\pi}{20}} \cdot \frac{1}{\tan \frac{\pi}{20}} \] ### Step 5: Cancel out terms Now, we can cancel \( \tan \frac{\pi}{20} \) with \( \frac{1}{\tan \frac{\pi}{20}} \) and \( \tan \frac{3\pi}{20} \) with \( \frac{1}{\tan \frac{3\pi}{20}} \): \[ \tan \frac{5\pi}{20} = \tan \frac{\pi}{4} \] ### Step 6: Evaluate \( \tan \frac{\pi}{4} \) We know that: \[ \tan \frac{\pi}{4} = 1 \] ### Final Result Thus, the value of the original expression is: \[ 1 \]

To find the value of \( \tan \frac{\pi}{20} \tan \frac{3\pi}{20} \tan \frac{5\pi}{20} \tan \frac{7\pi}{20} \tan \frac{9\pi}{20} \), we can follow these steps: ### Step 1: Write the expression We start with the expression: \[ \tan \frac{\pi}{20} \tan \frac{3\pi}{20} \tan \frac{5\pi}{20} \tan \frac{7\pi}{20} \tan \frac{9\pi}{20} \] ...
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