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Number of values of x satisfying the pai...

Number of values of `x` satisfying the pair of quadratic equations `x^(2)-px+20=0` and `x^(2)-20x+p=0` for some `p in R` is

A

`0`

B

`1`

C

`2`

D

`3`

Text Solution

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The correct Answer is:
To find the number of values of \( x \) satisfying the pair of quadratic equations 1. \( x^2 - px + 20 = 0 \) 2. \( x^2 - 20x + p = 0 \) for some \( p \in \mathbb{R} \), we can analyze the equations step by step. ### Step 1: Analyze the equations The two equations are: 1. \( x^2 - px + 20 = 0 \) (Equation 1) 2. \( x^2 - 20x + p = 0 \) (Equation 2) ### Step 2: Set the equations equal To find the relationship between \( p \) and \( x \), we can subtract Equation 1 from Equation 2: \[ (x^2 - 20x + p) - (x^2 - px + 20) = 0 \] This simplifies to: \[ -p + px - 20 + p = 0 \] Which further simplifies to: \[ (px - 20) = 0 \] ### Step 3: Solve for \( p \) From \( px - 20 = 0 \), we can express \( p \) in terms of \( x \): \[ p = \frac{20}{x} \quad (x \neq 0) \] ### Step 4: Substitute \( p \) back into one of the equations Now, we can substitute \( p \) back into either of the original equations. Let's substitute into Equation 1: \[ x^2 - \left(\frac{20}{x}\right)x + 20 = 0 \] This simplifies to: \[ x^2 - 20 + 20 = 0 \] Thus, we have: \[ x^2 = 0 \] ### Step 5: Solve for \( x \) Taking the square root of both sides gives: \[ x = 0 \] ### Step 6: Consider the case when \( p = 20 \) If we set \( p = 20 \), both equations become identical: \[ x^2 - 20x + 20 = 0 \] We can find the roots of this equation using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{20 \pm \sqrt{20^2 - 4 \cdot 1 \cdot 20}}{2 \cdot 1} \] Calculating the discriminant: \[ 20^2 - 80 = 400 - 80 = 320 \] Thus, the roots are: \[ x = \frac{20 \pm \sqrt{320}}{2} = \frac{20 \pm 8\sqrt{5}}{2} = 10 \pm 4\sqrt{5} \] ### Conclusion Now we have two cases: 1. When \( p \) is any real number except 20, we have one solution \( x = 0 \). 2. When \( p = 20 \), we have two solutions \( x = 10 + 4\sqrt{5} \) and \( x = 10 - 4\sqrt{5} \). Thus, the total number of distinct values of \( x \) satisfying the equations is: - 1 value when \( p \neq 20 \) - 2 values when \( p = 20 \) The total number of values of \( x \) satisfying the equations is **2**.

To find the number of values of \( x \) satisfying the pair of quadratic equations 1. \( x^2 - px + 20 = 0 \) 2. \( x^2 - 20x + p = 0 \) for some \( p \in \mathbb{R} \), we can analyze the equations step by step. ### Step 1: Analyze the equations ...
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