If the equation `4x^2-x-1=0 and 3x^2+(lambda+mu)x+lambda-mu=0`
have a root common, then the irrational values of `lambda and mu`
are
(a) `lambda=(-3)/4`
b. `lambda=0`
c. `mu=3/4`
b.`mu=0`
A
`lambda=0`, `mu=(-3)/(4)`
B
`lambda=(-3)/(4)`, `mu=(3)/(4)`
C
`lambda=(-3)/(4)`, `mu=0`
D
`lambda=(-3)/(4)`, `mu=(1)/(4)`
Text Solution
Verified by Experts
The correct Answer is:
C
`(c )` Roots of `4x^(2)-x-1=0` are irrational. So, one root common implies both roots are common. `:. (4)/(3)=(-1)/(lambda+mu)=(-1)/(lambda-mu)=(-2)/(2lambda)=(0)/(2mu)` So, `lambda=(-3)/(4)`, `mu=0`
