If bot the roots of `lamda(6x^(2)+3)rx+2x^(2)-1=0` and `6 lamda(2x^(2)+1)+px+4x^(2)-2=0` are common, then `2r-p` is equal to
A
`-1`
B
`0`
C
`1`
D
`2`
Text Solution
Verified by Experts
The correct Answer is:
B
`(b)` Given equation can be written as `(6k+2)x^(2)+rx+3k-1=0`………`(i)` and `2(6k+2)x^(2)+px+2(3k-1)=0`……….`(ii)` Condition for common roots is `(12k+4)/(6k+2)=(p)/(r )=(6k-2)/(3k-1)=2` or `2r-p=0`
CENGAGE ENGLISH|Exercise ARCHIVES (NUMERICAL VALUE TYPE)|1 Videos
THREE DIMENSIONAL GEOMETRY
CENGAGE ENGLISH|Exercise All Questions|294 Videos
Similar Questions
Explore conceptually related problems
p, q, r and s are integers. If the A.M. of the roots of x^(2) - px + q^(2) = 0 and G.M. of the roots of x^(2) - rx + s^(2) = 0 are equal, then
If x^(2)-6x+5=0 and x^(2)-3ax+35=0 have common root, then find a.
If alpha,beta are the roots of the equation lamda(x^(2)-x)+x+5=0 and if lamda_(1) and lamda_(2) are two values of lamda obtained from (alpha)/(beta)+(beta)/(alpha)=4 , then (lamda_(1))/(lamda_(2)^(2))+(lamda_(2))/(lamda_(1)^(2)) equals.
If sin theta, cos theta are the roots of 6x^(2)-px+1=0 , then p^(2) =
If the equadratic equation 4x ^(2) -2x -m =0 and 4p (q-r) x ^(2) -2p (r-p) x+r (p-q)-=0 have a common root such that second equation has equal roots then the vlaue of m will be :
If the equadratic equation 4x ^(2) -2x -m =0 and 4p (q-r) x ^(2) -2p (r-p) x+r (p-q)-=0 have a common root such that second equation has equal roots then the vlaue of m will be :
If alpha, beta are the roots fo the equation lamda(x^(2)-x)+x+5=0 . If lamda_(1) and lamda_(2) are two values of lamda for which the roots alpha, beta are related by (alpha)/(beta)+(beta)/(alpha)=4/5 find the value of (lamda_(1))/(lamda_(2))+(lamda_(2))/(lamda_(1))
If the equations x^(3)+5x^(2)+px+q=0 and x^(3)+7x^(2)+px+r=0 (a,q,r in R) have exactly two roots common,then p:q:r is
IF the equations x^(3) + 5x^(2) + px + q = 0 and x^(3) + 7x^(2) + px + r = 0 have two roots in common, then the product of two non-common roots of two equations, is
If p,q are roots of the quadratic equation x^(2)-10rx -11s =0 and r,s are roots of x^(2)-10px -11q=0 then find the value of p+q +r+s.
CENGAGE ENGLISH-THEORY OF EQUATIONS-JEE ADVANCED (Numerical Value Type )