A quadratic equations `p(x)=0` having coefficient `x^(2)` unity is such that `p(x)=0` and `p(p(p(x)))=0` have a common root, then
A
`p(0) p(1) gt 0`
B
`p(0) p(1) lt 0`
C
`p(0) p(1) = 0`
D
`p(0)=0` and `p(1)=0`
Text Solution
Verified by Experts
The correct Answer is:
C
`(c )` let `p(x)=x^(2)+ax+b` and let `alpha` be the common root `:. P(alpha)=0` and `p(p(p(alpha)))=0impliesp(p(0))=0` `implies p(alpha)=0` Now `p(0)=b` `:. P(b)=0` ,brgt `implies b^(2)+ab+b=0` `implies b(b+a+1)=0` `implies p(0)p(1)=0`
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