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If f(x) is a polynomial of degree four ...

If f(x) is a polynomial of degree four with leading coefficient one satisfying `f(1)=1, f(2)=2,f(3)=3`.then `[(f(-1)+f(5))/(f(0)+f(4))]`

A

`4`

B

`5`

C

`6`

D

`7`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the value of \(\frac{f(-1) + f(5)}{f(0) + f(4)}\) given that \(f(x)\) is a polynomial of degree 4 with leading coefficient 1 and satisfies \(f(1) = 1\), \(f(2) = 2\), and \(f(3) = 3\). ### Step 1: Formulate the Polynomial Since \(f(x)\) is a polynomial of degree 4 with leading coefficient 1, we can express it as: \[ f(x) = x^4 + ax^3 + bx^2 + cx + d \] ### Step 2: Use the Given Conditions We know: - \(f(1) = 1\) - \(f(2) = 2\) - \(f(3) = 3\) From these conditions, we can derive that: \[ f(x) - x = 0 \text{ for } x = 1, 2, 3 \] This means that \(f(x) - x\) has roots at \(x = 1, 2, 3\). Therefore, we can express: \[ f(x) - x = k(x-1)(x-2)(x-3)(x-r) \] where \(r\) is another root and \(k\) is a constant. ### Step 3: Determine the Leading Coefficient Since the leading coefficient of \(f(x)\) is 1, we have \(k = 1\). Thus: \[ f(x) - x = (x-1)(x-2)(x-3)(x-r) \] This implies: \[ f(x) = (x-1)(x-2)(x-3)(x-r) + x \] ### Step 4: Expand the Polynomial Now, we expand \((x-1)(x-2)(x-3)\): \[ (x-1)(x-2) = x^2 - 3x + 2 \] \[ (x^2 - 3x + 2)(x-3) = x^3 - 6x^2 + 11x - 6 \] Thus: \[ f(x) = (x^3 - 6x^2 + 11x - 6)(x - r) + x \] Expanding this gives: \[ f(x) = x^4 - rx^3 - 6x^3 + 6rx^2 + 11x^2 - 11rx - 6x + 6r + x \] Combining like terms: \[ f(x) = x^4 + (-r - 6)x^3 + (6r + 11)x^2 + (-11r - 5)x + 6r \] ### Step 5: Calculate \(f(-1)\), \(f(0)\), \(f(4)\), and \(f(5)\) 1. **Calculate \(f(-1)\)**: \[ f(-1) = (-1)^4 + (-r - 6)(-1)^3 + (6r + 11)(-1)^2 + (-11r - 5)(-1) + 6r \] Simplifying gives: \[ f(-1) = 1 + (r + 6) + (6r + 11) + (11r + 5) + 6r = 24r + 23 \] 2. **Calculate \(f(0)\)**: \[ f(0) = 6r \] 3. **Calculate \(f(4)\)**: \[ f(4) = 4^4 + (-r - 6)(4^3) + (6r + 11)(4^2) + (-11r - 5)(4) + 6r \] Simplifying gives: \[ f(4) = 256 + (-r - 6)(64) + (6r + 11)(16) + (-11r - 5)(4) + 6r \] After simplification, we find \(f(4) = 6(4 - r) + 256\). 4. **Calculate \(f(5)\)**: \[ f(5) = 5^4 + (-r - 6)(5^3) + (6r + 11)(5^2) + (-11r - 5)(5) + 6r \] After simplification, we find \(f(5) = 6(5 - r) + 625\). ### Step 6: Substitute Values into the Expression Now we substitute the values into the expression: \[ \frac{f(-1) + f(5)}{f(0) + f(4)} = \frac{(24r + 23) + (6(5 - r) + 625)}{6r + (6(4 - r) + 256)} \] ### Step 7: Simplify the Expression After simplifying the numerator and denominator, we will find the final value. ### Final Step: Calculate the Greatest Integer Finally, we compute the greatest integer value of the simplified expression.

To solve the problem, we need to find the value of \(\frac{f(-1) + f(5)}{f(0) + f(4)}\) given that \(f(x)\) is a polynomial of degree 4 with leading coefficient 1 and satisfies \(f(1) = 1\), \(f(2) = 2\), and \(f(3) = 3\). ### Step 1: Formulate the Polynomial Since \(f(x)\) is a polynomial of degree 4 with leading coefficient 1, we can express it as: \[ f(x) = x^4 + ax^3 + bx^2 + cx + d \] ...
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