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The number of distinct terms in the expa...

The number of distinct terms in the expansion of is `(x^(3)+(1)/(x^(3))+1)^(200)` is (a) 201 (b) 400 (c) 401 (d) 500

A

`201`

B

`400`

C

`401`

D

`500`

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of distinct terms in the expansion of \((x^3 + \frac{1}{x^3} + 1)^{200}\), we can follow these steps: ### Step 1: Identify the expression We start with the expression: \[ (x^3 + \frac{1}{x^3} + 1)^{200} \] ### Step 2: Substitute variables Let \( t = x^3 \). Then, we can rewrite the expression as: \[ (t + \frac{1}{t} + 1)^{200} \] ### Step 3: Analyze the binomial expansion The expression \((t + \frac{1}{t} + 1)^{200}\) can be expanded using the multinomial theorem. The general term in the expansion can be expressed as: \[ \frac{200!}{a!b!c!} t^a \left(\frac{1}{t}\right)^b 1^c \] where \( a + b + c = 200 \). ### Step 4: Simplify the general term The general term simplifies to: \[ \frac{200!}{a!b!c!} t^{a-b} \] This means that the exponent of \( t \) (which is \( x^3 \)) will be \( a - b \). ### Step 5: Determine the range of \( a - b \) The values of \( a \) and \( b \) can range from \( 0 \) to \( 200 \). Therefore: - The minimum value of \( a - b \) occurs when \( a = 0 \) and \( b = 200 \), giving \( a - b = 0 - 200 = -200 \). - The maximum value of \( a - b \) occurs when \( a = 200 \) and \( b = 0 \), giving \( a - b = 200 - 0 = 200 \). ### Step 6: Calculate the distinct values of \( a - b \) The possible values of \( a - b \) range from \( -200 \) to \( 200 \). This gives us: \[ 200 - (-200) + 1 = 200 + 200 + 1 = 401 \] ### Conclusion Thus, the number of distinct terms in the expansion of \((x^3 + \frac{1}{x^3} + 1)^{200}\) is \( 401 \). ### Final Answer The answer is \( \boxed{401} \).

To find the number of distinct terms in the expansion of \((x^3 + \frac{1}{x^3} + 1)^{200}\), we can follow these steps: ### Step 1: Identify the expression We start with the expression: \[ (x^3 + \frac{1}{x^3} + 1)^{200} \] ...
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