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If a,b,c,d be four consecutive coefficie...

If `a,b,c,d` be four consecutive coefficients in the binomial expansion of `(1+x)^(n)`, then value of the expression `(((b)/(b+c))^(2)-(ac)/((a+b)(c+d)))` (where `x gt 0` and `n in N`) is

A

positive

B

negative

C

zero

D

depends on `n`

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To solve the given problem, we need to find the value of the expression \[ \left(\frac{b}{b+c}\right)^2 - \frac{ac}{(a+b)(c+d)} \] where \(a, b, c, d\) are four consecutive coefficients in the binomial expansion of \((1+x)^n\). ### Step 1: Identify the coefficients The coefficients in the binomial expansion are given by: - \(a = \binom{n}{r-1}\) - \(b = \binom{n}{r}\) - \(c = \binom{n}{r+1}\) - \(d = \binom{n}{r+2}\) ### Step 2: Express \(b+c\) and \(c+d\) Using the properties of binomial coefficients, we can express: - \(b + c = \binom{n}{r} + \binom{n}{r+1} = \binom{n+1}{r+1}\) (using Pascal's identity) - \(c + d = \binom{n}{r+1} + \binom{n}{r+2} = \binom{n+1}{r+2}\) ### Step 3: Substitute into the expression Now we substitute these values into the expression: \[ \left(\frac{b}{b+c}\right)^2 = \left(\frac{\binom{n}{r}}{\binom{n+1}{r+1}}\right)^2 \] And for the second part: \[ ac = \binom{n}{r-1} \cdot \binom{n}{r+1} \] Now substituting \(a + b\) and \(c + d\): \[ (a+b)(c+d) = \binom{n}{r-1} + \binom{n}{r} \cdot \binom{n}{r+1} + \binom{n}{r+2} = \binom{n+1}{r} \cdot \binom{n+1}{r+1} \] ### Step 4: Simplify the expression Now we can rewrite the expression: \[ \left(\frac{\binom{n}{r}}{\binom{n+1}{r+1}}\right)^2 - \frac{\binom{n}{r-1} \cdot \binom{n}{r+1}}{\binom{n+1}{r} \cdot \binom{n+1}{r+1}} \] ### Step 5: Find a common denominator The common denominator for both terms is \(\binom{n+1}{r+1}^2\): \[ \frac{\binom{n}{r}^2 - \binom{n}{r-1} \cdot \binom{n}{r+1}}{\binom{n+1}{r+1}^2} \] ### Step 6: Use the identity for binomial coefficients Using the identity \(\binom{n}{r}^2 - \binom{n}{r-1} \cdot \binom{n}{r+1} = \binom{n-1}{r-1}\): \[ \frac{\binom{n-1}{r-1}}{\binom{n+1}{r+1}^2} \] ### Step 7: Final simplification We can conclude that the expression simplifies to a non-negative value, and since \(n\) and \(r\) are natural numbers, the value of the entire expression is \(0\). ### Final Answer The value of the expression is \(0\). ---

To solve the given problem, we need to find the value of the expression \[ \left(\frac{b}{b+c}\right)^2 - \frac{ac}{(a+b)(c+d)} \] where \(a, b, c, d\) are four consecutive coefficients in the binomial expansion of \((1+x)^n\). ...
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