Home
Class 12
MATHS
The value of the sum ""^(1000)C(50) + ""...

The value of the sum `""^(1000)C_(50) + ""^(999)C_(49) +""^(998)C_(48)+"…."""^(950)C_(0)` is

A

`"^(1001)C_(50)`

B

`"^(1002)C_(951)-^(1001)C_(51)`

C

`"^(1001)C_(951)`

D

`"^(1002)C_(51)-^(1001)C_(95)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

`(a,b,c,d)` `'^(1000)C_(50)+^(999)C_(40)+^(998)C_(48)+....+^(950)C_(0)`
`="coefficient of" x^(950) "in" {(1+x)^(950)+(1+x)^(951)+…+(1+x)^(1000)}`
`="coefficient of" x^(950) "in" (1+x)^(950){1+(1+x)+(1+x)^(2)+….+(1+x)^(50)}`
`="coefficient of" x^(950) "in" (1+x)^(950) ({(1+x)^(51)-1})/(1+x-1)`
`="coefficient of" x^(950) "in" ((1+x)^(1001)-(1+x)^(950))/(x)`
`=^(1000)C_(951)=^(1001)C_(50)=^(1002)C_(951)-^(1001)C_(51)=^(1002)C_(51)-^(1001)C_(950)`, Since `'^(n)C_(r )+^(n)C_(r-1)=^((n+1))C_(r )`
Promotional Banner

Topper's Solved these Questions

  • BINOMIAL THEOREM

    CENGAGE ENGLISH|Exercise Comprehension|11 Videos
  • BINOMIAL THEOREM

    CENGAGE ENGLISH|Exercise Matrix|4 Videos
  • BINOMIAL THEOREM

    CENGAGE ENGLISH|Exercise Archives|16 Videos
  • AREA

    CENGAGE ENGLISH|Exercise Comprehension Type|2 Videos
  • CIRCLE

    CENGAGE ENGLISH|Exercise MATRIX MATCH TYPE|7 Videos

Similar Questions

Explore conceptually related problems

The sum ""^(40)C_(0) + ""^(40)C_(1)+""^(40)C_(2)+…+""^(40)C_(20) is equal to

The sum ""^(20)C_(0)+""^(20)C_(1)+""^(20)C_(2)+……+""^(20)C_(10) is equal to :

The value of sum_(r=2)^(10) ""^(r)C_(2).""^(10)C_(r) is

Find the value of : ""^(50)C_(47)

The sum of the series ""^(4)C_(0) + ""^(5)C_(1) x + ""^(6)C_(2) x^(2)+""^(7)C_(3)x^(3) +... to infty , is

The value of ((""^(50)C_(0))/(1)+(""^(50)C_(2))/(3)+(""^(50)C_(4))/(5)+….+(""^(50)C_(50))/(51)) is :

Let q be a positive with q le 50 . If the sum ""^(98)C_(30)+2" "^(97)C_(30)+3." "^(96)C_(30)+ …… + 68." "^(31)C_(30)+69." "^(30)C_(30)=""^(100)C_(q) Find the sum of the digits of q.

The value of sum_(r=1)^(10) r. (""^(n)C_(r))/(""^(n)C_(r-1) is equal to

The value of sum_(r=0)^(3) ""^(8)C_(r)(""^(5)C_(r+1)-""^(4)C_(r)) is "_____" .

The value of sum_(r=0)^(40) r""^(40)C_(r)""^(30)C_(r) is (a) 40.^(69)C_(29) (b) 40.^(70)C_(30) (c) .^(60)C_(29) (d) .^(70)C_(30)