find the point on the curve `y=2x^2-6x-4` at which the tangent is parallel to the x-axis

Answer

A, B, C, D

Explanation

a. `[x]^(2)=[y]^(2)," where "1le x le4`
`rArr" "[x]=pm[y]`

b. `[|x|]+[|y|]=2`
The graph is symmetrical about both x-axis and y-axis.
`"For "x,ygt0,[x]+[y]=2.`
`rArr" "[x]=0 and [y]=2,[x]=1 and [y]=1 or [x]=2 and [y]=0`.

c. `[|x|][|y|]=2`
The graph is symmetrical about both x-axis and y-axis.
`"For "x,ygt0,[x][y]=2`
`rArr" "[x]=1 and [y]=2 or [x] = 2 and [y]=1.`

d. `([|x|])/([|y|])=2," where "-5lexle5.`
The graph is symmetrical about both the axes.
`"For "x,ygt0,[x]=2[y],[y]ne0`.
`rArr" "[x]=2 and [y]=1 or [x]=4 and [y]=2.`