If `A` is the area bounded by the curves `y=sqrt(1-x^2)` and `y=x^3-x` , then of `pi/Adot`

Answer

2

Explanation

`y=sqrt(1-x^(2))" (1)"`
`y=x^(3)-x" (2)"`
`y=0" in "(2) x=0, 1,-1`

Required area = Area of region BCAGOHB
=Area of semi-circle BCAOB
`=(pi)/(2)" "(because" area of BHOEB= area of OFAGO")`