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Equation of the straight line meeting th...

Equation of the straight line meeting the cirle with centre at origin and radius equal to 5 in two points at equal distances of 3 units from the point (3,4) is

A

`6x +8y = 41`

B

`6x - 8y +41 = 0`

C

`8x +6y +41 = 0`

D

`8x -6y +41 = 0`

Text Solution

Verified by Experts

The correct Answer is:
A

Equation of circle whose centre is at (3,4) and radius is equal to 3 is `(x-3)^(2) + (y-4)^(2) =9`
Given circle is `x^(2) +y^(2) = 25`.
Now the equation of straight line is the common chord of the two circles.
`rArr 6x +8y = 41`
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