Home
Class 12
MATHS
Let A (0,2),B and C be points on parabol...

Let `A (0,2),B` and C be points on parabola `y^(2)+x +4` such that `/_CBA (pi)/(2)`. Then the range of ordinate of C is (a) `(-oo,0)uu (4,oo)` (b) `(-oo,0] uu[4,oo)` (c) `[0,4]` (d) `(-oo,0)uu [4,oo)`

A

`(-oo,0)uu (4,oo)`

B

`(-oo,0] uu[4,oo)`

C

`[0,4]`

D

`(-oo,0)uu [4,oo)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the range of the ordinate (y-coordinate) of point C on the parabola defined by the equation \( y^2 + x + 4 = 0 \) given that the angle \( \angle CBA = \frac{\pi}{2} \). ### Step-by-Step Solution: 1. **Rearranging the Parabola Equation**: The equation of the parabola can be rearranged to express \( x \) in terms of \( y \): \[ x = -y^2 - 4 \] 2. **Identifying Points A, B, and C**: - Point \( A \) is given as \( A(0, 2) \). - Let point \( B \) be \( B(t_1^2 - 4, t_1) \) and point \( C \) be \( C(t_2^2 - 4, t_2) \), where both points lie on the parabola. 3. **Finding Slopes**: - The slope of line segment \( AB \) is given by: \[ m_{AB} = \frac{y_B - y_A}{x_B - x_A} = \frac{t_1 - 2}{t_1^2 - 4 - 0} = \frac{t_1 - 2}{t_1^2 - 4} \] - The slope of line segment \( CB \) is given by: \[ m_{CB} = \frac{y_C - y_B}{x_C - x_B} = \frac{t_2 - t_1}{t_2^2 - 4 - (t_1^2 - 4)} = \frac{t_2 - t_1}{t_2^2 - t_1^2} \] 4. **Condition for Perpendicularity**: Since \( \angle CBA = \frac{\pi}{2} \), the slopes must satisfy: \[ m_{AB} \cdot m_{CB} = -1 \] This leads to: \[ \left(\frac{t_1 - 2}{t_1^2 - 4}\right) \cdot \left(\frac{t_2 - t_1}{t_2^2 - t_1^2}\right) = -1 \] 5. **Solving the Equation**: Rearranging and simplifying the equation leads to a quadratic equation in terms of \( t_1 \) and \( t_2 \). After solving, we find: \[ t_1^2 + 2t_2 + 1 = 0 \] This indicates a relationship between \( t_1 \) and \( t_2 \). 6. **Finding the Range of \( t_2 \)**: The discriminant of the quadratic must be non-negative for real solutions: \[ 2^2 - 4(1)(-t_2) \geq 0 \implies 4 + 4t_2 \geq 0 \implies t_2 \geq -1 \] However, since \( t_2 \) represents the ordinate of point \( C \) on the parabola, we also need to consider the shape of the parabola. 7. **Final Range for Ordinate of C**: The parabola opens to the left, and thus the y-values can be: \[ y_C \in (-\infty, 0) \cup [4, \infty) \] ### Conclusion: The range of the ordinate of point C is: \[ (-\infty, 0) \cup [4, \infty) \] Thus, the correct option is **(d) \((-∞, 0) \cup [4, ∞)\)**.

To solve the problem, we need to find the range of the ordinate (y-coordinate) of point C on the parabola defined by the equation \( y^2 + x + 4 = 0 \) given that the angle \( \angle CBA = \frac{\pi}{2} \). ### Step-by-Step Solution: 1. **Rearranging the Parabola Equation**: The equation of the parabola can be rearranged to express \( x \) in terms of \( y \): \[ x = -y^2 - 4 ...
Promotional Banner

Topper's Solved these Questions

  • PARABOLA

    CENGAGE ENGLISH|Exercise Multiple Correct Answers Type|10 Videos
  • PARABOLA

    CENGAGE ENGLISH|Exercise Comprehension Type|2 Videos
  • PARABOLA

    CENGAGE ENGLISH|Exercise MULTIPLE CORRECT ANSWER TYPE|7 Videos
  • PAIR OF STRAIGHT LINES

    CENGAGE ENGLISH|Exercise Numberical Value Type|5 Videos
  • PERMUTATION AND COMBINATION

    CENGAGE ENGLISH|Exercise Comprehension|8 Videos

Similar Questions

Explore conceptually related problems

The solution set of the inequality max {1-x^2,|x-1|}<1 is (-oo,0)uu(1,oo) (b) (-oo,0)uu(2,oo) (0,2) (d) (0,2)

The range of the function f(x)=|x-1| is A. (-oo,0) B. [0,oo) C. (0,oo) D. R

The set of points where the function f(x)=x|x| is differentiable is (a) (-oo,\ oo) (b) (-oo,\ 0)uu(0,\ oo) (c) (0,\ oo) (d) [0,\ oo]

For x^2-(a+3)|x|-4=0 to have real solutions, the range of a is a) (-oo,-7]uu[1,oo) b) (-3,oo) c) (-oo,-7] d) [1,oo)

If (log)_3(x^2-6x+11)lt=1, then the exhaustive range of values of x is: (a) (-oo,2)uu(4,oo) (b) (2,4) (c) (-oo,1)uu(1,3)uu(4,oo) (d) none of these

The set of points where the function f(x)=x|x| is differentiable is (-oo,oo) (b) (-oo,0)uu(0,oo) (0,oo) (d) [0,oo)

The interval of increase of the function f(x)=x-e^x+tan(2pi//7) is (a) (0,\ oo) (b) (-oo,\ 0) (c) (1,\ oo) (d) (-oo,\ 1)

The domain of f(x)="log"|logx|i s (0,oo) (b) (1,oo) (c) (0,1)uu(1,oo) (d) (-oo,1)

If 0ltalphaltpi/4 then the range of cosec 2alpha-cot 2alpha is (A) (0,1) (B) [1,oo) (C) RR (D) [0,oo)

f(x)=(x-2)|x-3| is monotonically increasing in (a) (-oo,5/2)uu(3,oo) (b) (5/2,oo) (c) (2,oo) (d) (-oo,3)

CENGAGE ENGLISH-PARABOLA-Single Correct Answer Type
  1. If AFB is a focal chord of the parabola y^(2) = 4ax such that AF = 4 a...

    Text Solution

    |

  2. Length of the focal chord of the parabola (y +3)^(2) = -8(x-1) which l...

    Text Solution

    |

  3. Let A (0,2),B and C be points on parabola y^(2)+x +4 such that /CBA (...

    Text Solution

    |

  4. lx +my = 1 is the equation of the chord PQ of y^(2) = 4x whose focus i...

    Text Solution

    |

  5. A line from (-1,0) intersects the parabola x^(2)= 4y at A and B. Then ...

    Text Solution

    |

  6. All the three vertices of an equilateral triangle lie on the parabola ...

    Text Solution

    |

  7. Find the equations of the chords of the parabola y^2= 4ax which pass t...

    Text Solution

    |

  8. Two equal circles of largest radii have following property: (i) They...

    Text Solution

    |

  9. Let P and Q are points on the parabola y^(2)=4ax with vertex O, such t...

    Text Solution

    |

  10. A line ax +by +c = 0 through the point A(-2,0) intersects the curve y^...

    Text Solution

    |

  11. Suppose a parabola y = x^(2) - ax-1 intersects the coordinate axes at ...

    Text Solution

    |

  12. The line x - b +lambda y = 0 cuts the parabola y^(2) = 4ax (a gt 0) at...

    Text Solution

    |

  13. If the parabola y=(a-b)x^2+(b-c)x+(c-a) touches x- axis then the line...

    Text Solution

    |

  14. A normal to parabola, whose inclination is 30^(@), cuts it again at an...

    Text Solution

    |

  15. If (-2,5) and (3,7) are the points of intersection of the tangent and ...

    Text Solution

    |

  16. The angle of intersection between the curves x^(2) = 4(y +1) and x^(2)...

    Text Solution

    |

  17. The parabolas y^2=4ax and x^2=4by intersect orthogonally at point P(x1...

    Text Solution

    |

  18. Sum of slopes of common tangent to y = (x^(2))/(4) - 3x +10 and y = 2 ...

    Text Solution

    |

  19. The slope of normal to be parabola y = (x^(2))/(4) -2 drawn through th...

    Text Solution

    |

  20. The tangent and normal at the point P(4,4) to the parabola, y^(2) = 4x...

    Text Solution

    |