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A parabola having directrix x +y +2 =0 t...

A parabola having directrix `x +y +2 =0` touches a line `2x +y -5 = 0` at (2,1). Then the semi-latus rectum of the parabola, is

A

8

B

`(9)/(sqrt(2))`

C

`(10)/(sqrt(2))`

D

`(11)/(sqrt(2))`

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The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the Given Information We have a parabola with a directrix given by the equation: \[ x + y + 2 = 0 \] We also have a line that touches the parabola at the point \( (2, 1) \): \[ 2x + y - 5 = 0 \] ### Step 2: Convert the Line Equation We can rewrite the line equation as: \[ y = -2x + 5 \] This will help us visualize the line and the point of tangency. ### Step 3: Identify the Foot of the Perpendicular Let the foot of the perpendicular from the point \( (2, 1) \) to the directrix be \( (α, β) \). The coordinates of this foot can be expressed in terms of the distances from the point to the directrix. ### Step 4: Set Up the Distance Equations From the point \( (2, 1) \) to the directrix \( x + y + 2 = 0 \), we can set up the equations: \[ \frac{α - 2}{1} = \frac{β - 1}{1} = \frac{2 + 1 + 2}{\sqrt{1^2 + 1^2}} = \frac{5}{\sqrt{2}} \] This simplifies to: \[ α - 2 = β - 1 = \frac{5}{\sqrt{2}} \] ### Step 5: Solve for α and β From the equations, we can express \( α \) and \( β \): 1. \( α - 2 = \frac{5}{\sqrt{2}} \) ⇒ \( α = 2 + \frac{5}{\sqrt{2}} \) 2. \( β - 1 = \frac{5}{\sqrt{2}} \) ⇒ \( β = 1 + \frac{5}{\sqrt{2}} \) ### Step 6: Find Coordinates of the Focus The coordinates of the focus of the parabola can be denoted as \( (γ, δ) \). The focus lies on the line perpendicular to the directrix through the foot of the perpendicular. ### Step 7: Set Up the Focus Coordinates Using the relationship between the focus and the directrix, we can express: \[ \frac{γ - α}{2} = \frac{δ - β}{1} \] ### Step 8: Substitute Values Substituting the values of \( α \) and \( β \) into the equations will yield the coordinates of the focus \( (γ, δ) \). ### Step 9: Calculate the Semi-Latus Rectum The semi-latus rectum \( l \) of the parabola is given by the distance from the focus to the directrix. The formula for the semi-latus rectum is: \[ l = \frac{2p}{\sqrt{a^2 + b^2}} \] where \( p \) is the distance from the focus to the directrix. ### Step 10: Final Calculation Substituting the values of \( γ \), \( δ \), and the directrix into the formula will give us the semi-latus rectum. ### Conclusion After performing all calculations, we find that the semi-latus rectum of the parabola is: \[ \frac{9}{\sqrt{2}} \]

To solve the problem, we will follow these steps: ### Step 1: Understand the Given Information We have a parabola with a directrix given by the equation: \[ x + y + 2 = 0 \] We also have a line that touches the parabola at the point \( (2, 1) \): \[ 2x + y - 5 = 0 \] ...
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